x^2=4050

Solution for x^2=4050 equation:

x^2=4050

We move all terms to the left:

x^2-(4050)=0

a = 1; b = 0; c = -4050;
Δ = b2-4ac
Δ = 02-4·1·(-4050)
Δ = 16200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16200}=\sqrt{8100*2}=\sqrt{8100}*\sqrt{2}=90\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90\sqrt{2}}{2*1}=\frac{0-90\sqrt{2}}{2}
=-\frac{90\sqrt{2}}{2}
=-45\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90\sqrt{2}}{2*1}=\frac{0+90\sqrt{2}}{2}
=\frac{90\sqrt{2}}{2}
=45\sqrt{2}
$